Sunday, December 9, 2012

2012-12-09-aj problemoj

Hodiaŭaj problemoj (de la 25a al la 26a): Anand - Adams [4440.55] kaj Rodriguez - Timoshenko [4844.56].


000025. Viswanathan Anand (2775) - Michael Adams (2710). London Chess Classic (6.3), 2012.12.07.
9 + 9
FEN: 3q2k1/5p2/4b1p1/2R1p2p/1pB1P2P/1P2Q1P1/r4PK1/8 b - - 1 40
GRB: 4440.55 (KQRBKQRB_1010)
ECO: A29
PGN1. c4 e5 2. Nc3 Nf6 3. Nf3 Nc6 4. g3 g6 5. d4 exd4 6. Nxd4 Bg7 7. Bg2 O-O 8. O-O Re8 9. Nc2 d6 10. Bd2 a6 11. Rc1 Ne5 12. b3 c6 13. Be3 Nfg4 14. Bd4 c5 15. Bxe5 Bxe5 16. Nd5 Rb8 17. h3 Nf6 18. Nce3 Nxd5 19. Nxd5 Qa5 20. Rc2 Bf5 21. Qd2 Qd8 22. Rcc1 b5 23. cxb5 axb5 24. Rfd1 h5 25. h4 Bg4 26. Ne3 Bd7 27. Bf3 Bd4 28. Nd5 b4 29. Rc4 Be5 30. Kg2 Ra8 31. Ne3 Ra7 32. Rcc1 Qe7 33. Nc4 Be6 34. Rc2 Bf5 35. e4 Be6 36. Nxe5 dxe5 37. Qe3 Ra5 38. Be2 Rd8 39. Rxd8+ Qxd8 40. Rxc5 Rxa2 41. Bc4 Qd1 42. Qh6 Bh3+ 0-1
000026. Amador Rodríguez Céspedes - Georgy Timoshenko. Ubeda Op 3rd, 1998.01.20
11 + 12
FEN: 3r1k2/1BQ2p1p/p2p1qnb/1p6/4p1r1/2P5/PPN2P1P/4RK1R b - - 1 26
GRB: 4844.56 (KQRRBNKQRRBN_1001)
ECO: B33
PGN: 1.e4 c5 2.Nf3 e6 3.d4 cxd4 4.Nxd4 Nf6 5.Nc3 Nc6 6.Ndb5 d6 7.Bf4 e5 8.Bg5 a6 9.Na3 b5 10.Bxf6 gxf6 11.Nd5 f5 12.Bd3 Be6 13.Qh5 Rg8 14.c3 Rxg2 15.Qf3 Rg4 16.exf5 Bxd5 17.Qxd5 Ne7 18.Qb7 Bh6 19.f6 Ng8 20.Be4 Rb8 21.Qc6+ Kf8 22.Rd1 Qxf6 23.Kf1 Rd8 24.Nc2 Ne7 25.Qc7 Ng6 26.Bb7 e4 27.Re1 Qf3 28.Qxd8+ Kg7 29.Nd4 Qh3+ 0-1

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